using System;
using System.Collections.Generic;
using System.Linq;
namespace Link.Common
{
///
/// 地址工具
///
public class LinkUtil
{
///
/// 基础62位字符
///
private const string _baseKeys = "ABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789abcdefghijklmnopqrstuvwxyz";
///
/// 幂数
///
private static readonly int _exponent = _baseKeys.Length;
///
/// 十进制转62进制
///
///
///
public static string ConvertTo64(long value)
{
string result = string.Empty;
do
{
long index = value % _exponent;
result = _baseKeys[(int)index] + result;
value = (value - index) / _exponent;
}
while (value > 0);
return result;
}
///
/// 混淆十进制转62进制
///
///
///
public static string MixValueConvertTo64(long value)
{
long mixValue = InsertRandomBitPer5Bits(value);
string result = string.Empty;
do
{
long index = mixValue % _exponent;
result = _baseKeys[(int)index] + result;
mixValue = (mixValue - index) / _exponent;
}
while (mixValue > 0);
return result;
}
///
/// 62进制转10进制
///
///
///
public static decimal ConvertTo10(string value)
{
decimal result = 0;
for (int i = 0; i < value.Length; i++)
{
int x = value.Length - i - 1;
result += _baseKeys.IndexOf(value[i]) * Pow(_exponent, x);
}
return result;
}
///
/// 一个数据的N次方
///
///
///
///
private static decimal Pow(decimal baseNo, decimal x)
{
//1 will be the result for any number's power 0.
decimal value = 1;
while (x > 0)
{
value = value * baseNo;
x--;
}
return value;
}
///
/// 每5位插一个随机位
///
///
///
private static long InsertRandomBitPer5Bits(long val)
{
long result = val;
long high = val;
for (int i = 0; i < 10; i++)
{
if (high == 0)
{
break;
}
Random random = new Random();
long num = random.Next(0, 2);
int pos = 5 + 5 * i + i;
high = result >> pos;
result = ((high << 1 | num) << pos) | (result & RightMove(-1L, 64 - pos));
}
return result;
}
///
/// 无符号右移, 相当于java里的 value>>>pos
///
///
///
///
public static long RightMove(long value, int pos)
{
//移动 0 位时直接返回原值
if (pos != 0)
{
// int.MaxValue = 0x7FFFFFFF 整数最大值
long mask = long.MaxValue;
//无符号整数最高位不表示正负但操作数还是有符号的,有符号数右移1位,正数时高位补0,负数时高位补1
value = value >> 1;
//和整数最大值进行逻辑与运算,运算后的结果为忽略表示正负值的最高位
value = value & mask;
//逻辑运算后的值无符号,对无符号的值直接做右移运算,计算剩下的位
value = value >> pos - 1;
}
return value;
}
}
}