using System; using System.Collections.Generic; using System.Linq; namespace Link.Common { /// /// 地址工具 /// public class LinkUtil { /// /// 基础62位字符 /// private const string _baseKeys = "ABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789abcdefghijklmnopqrstuvwxyz"; /// /// 幂数 /// private static readonly int _exponent = _baseKeys.Length; /// /// 十进制转62进制 /// /// /// public static string ConvertTo64(long value) { string result = string.Empty; do { long index = value % _exponent; result = _baseKeys[(int)index] + result; value = (value - index) / _exponent; } while (value > 0); return result; } /// /// 混淆十进制转62进制 /// /// /// public static string MixValueConvertTo64(long value) { long mixValue = InsertRandomBitPer5Bits(value); string result = string.Empty; do { long index = mixValue % _exponent; result = _baseKeys[(int)index] + result; mixValue = (mixValue - index) / _exponent; } while (mixValue > 0); return result; } /// /// 62进制转10进制 /// /// /// public static decimal ConvertTo10(string value) { decimal result = 0; for (int i = 0; i < value.Length; i++) { int x = value.Length - i - 1; result += _baseKeys.IndexOf(value[i]) * Pow(_exponent, x); } return result; } /// /// 一个数据的N次方 /// /// /// /// private static decimal Pow(decimal baseNo, decimal x) { //1 will be the result for any number's power 0. decimal value = 1; while (x > 0) { value = value * baseNo; x--; } return value; } /// /// 每5位插一个随机位 /// /// /// private static long InsertRandomBitPer5Bits(long val) { long result = val; long high = val; for (int i = 0; i < 10; i++) { if (high == 0) { break; } Random random = new Random(); long num = random.Next(0, 2); int pos = 5 + 5 * i + i; high = result >> pos; result = ((high << 1 | num) << pos) | (result & RightMove(-1L, 64 - pos)); } return result; } /// /// 无符号右移, 相当于java里的 value>>>pos /// /// /// /// public static long RightMove(long value, int pos) { //移动 0 位时直接返回原值 if (pos != 0) { // int.MaxValue = 0x7FFFFFFF 整数最大值 long mask = long.MaxValue; //无符号整数最高位不表示正负但操作数还是有符号的,有符号数右移1位,正数时高位补0,负数时高位补1 value = value >> 1; //和整数最大值进行逻辑与运算,运算后的结果为忽略表示正负值的最高位 value = value & mask; //逻辑运算后的值无符号,对无符号的值直接做右移运算,计算剩下的位 value = value >> pos - 1; } return value; } } }